All-time ‘Jeopardy!’ champs to vie for share of $1.5 million
 

All-time ‘Jeopardy!’ champs to vie for share of $1.5 million
LOS ANGELES (AP) — The three top money winners in “Jeopardy!” history will vie for a share of $1.5 million in January.

ABC and the quiz show’s producer said Monday that Ken Jennings, Brad Rutter and James Holzhauer will compete in prime-time episodes on the network.

The first contestant to win three matches will receive $1 million. Each runner-up will take home $250,000.

Alex Trebek will host the contest, titled “Jeopardy! The Greatest of All Time” and debuting 8 p.m. Eastern on Jan. 7.
But the GOAT tournament will be anything but typical: It consists of a series of two back-to-back games, airing weeknights (8 EST/PST) beginning Jan. 7. The player with the most combined winnings from the two games wins the “match,” and the play continues on successive nights (except Monday) until one of them has won three matches and takes home a $1 million prize. (The other finishers get $250,000 apiece). That means the tournament can last anywhere from three to seven days.

Rutter is the top all-time money winner with $4.7 million, followed by Jennings with $3.4 million and Holzhauer with $2.7 million.

I have penciled date in my Calendar as one of the must see events of the year

David- Thanks for sharing. I've become a big fan since James won all his money...including the recent Champions Tournament.

An intellectual competition with a classy host. Must See TV Indeed!


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