Kreindler raffle info, pg 8, post #79, this thread

[thecatspajamas]

Originally Posted by perezfan

I guess I'm brain-dead today, or did not stay at a Holiday Inn Express last night (or both...)

If the contest is limited to 200 entries, what if the attendance for the pre-selected game is is 28,917?

So the winning number is then 917... but the entries go from only 1 - 200. How will this determine a winner?

I'm sure there's an obvious answer... just not getting it

In that case, it would be whoever got #117, because they would also have #317, 517, 717 and 917. Every $20 entry gets you 5 numbers. You get your base number ranging from 1 through 200, and then add 200 each time to get your 4 other numbers.

200 was selected as the cap for entries because it's a nice round number and divides into 1000 easily, simplifying the math. And because Graig said the he could do a nice painting of that size for that price