Kreindler raffle info, pg 8, post #79, this thread

[perezfan]

Originally Posted by thecatspajamas

No drawing. Everyone gets their numbers assigned ahead of time, all posted on the board for all to see so that there is no cry of foul. The winning number is determined by taking the last 3 digits of the attendance figure for a pre-selected game as reported by a specific source.

So essentially an independent, verifiable random number (with a baseball theme for fun).

That way everything is laid out in advance, no board members have any control over the selection of the winning number, and there should be no cries of "foul" or any question of the results being manipulated.

I guess I'm brain-dead today, or did not stay at a Holiday Inn Express last night (or both...)

If the contest is limited to 200 entries, what if the attendance for the pre-selected game is is 28,917?

So the winning number is then 917... but the entries go from only 1 - 200. How will this determine a winner?

I'm sure there's an obvious answer... just not getting it

[Kawika]

In like a dirty shirt.

[T20Brew]

I would definitely be in for 1.

[bn2cardz]

Originally Posted by perezfan

I guess I'm brain-dead today, or did not stay at a Holiday Inn Express last night (or both...)

If the contest is limited to 200 entries, what if the attendance for the pre-selected game is is 28,917?

So the winning number is then 917... but the entries go from only 1 - 200. How will this determine a winner?

I'm sure there's an obvious answer... just not getting it

The full rules were laid out in the OP:

Originally Posted by billyb

3. Once total entries obtained, that number divided into 1000 to obtain a whole number. (example; 230 total into 1000 is 4.3), 4 is the whole number, meaning everyone will get 3 additional chances to win. The list will then be expanded by reapplying the numbers list starting with 231 (3 additional times), keeping list in same sequence.
4. Using the 230 as an example, Member who received #1, would also get 231, 461, and 691.
5. Using 230 as the example, the last number would be 920, Any number after 920 is not to be used.
6. Drawing: Once final list posted with all additional extra chances, posted for 3-5 days so everyone gets a chance to see the numbers, a ballbame, preselected will be named and the last three numbers of the attendance figure will be you winner. If those numbers fall is one of the unused numbers, the last number dropped from the attendance and the new three numbers will the winner.

[billyb]

Perez fan,
Each entry will get 5 chances. Once the list is established from 1-200, the named list is re-entered, in same order, 4 additional times. 5 x 200 = 1000.

[old13man]

Could be a stupid question but if we said we are in does that guarantee us an opportunity to buy in or will it be a mad scramble once its opened up? It seems like 200 will not be hard to fill at all.


CJ

[thecatspajamas]

Originally Posted by perezfan

I guess I'm brain-dead today, or did not stay at a Holiday Inn Express last night (or both...)

If the contest is limited to 200 entries, what if the attendance for the pre-selected game is is 28,917?

So the winning number is then 917... but the entries go from only 1 - 200. How will this determine a winner?

I'm sure there's an obvious answer... just not getting it

In that case, it would be whoever got #117, because they would also have #317, 517, 717 and 917. Every $20 entry gets you 5 numbers. You get your base number ranging from 1 through 200, and then add 200 each time to get your 4 other numbers.

200 was selected as the cap for entries because it's a nice round number and divides into 1000 easily, simplifying the math. And because Graig said the he could do a nice painting of that size for that price

[perezfan]

Got it... I'm in too (if room allows).

Thanks!

[autograf]

In for at least one, more if allowed..................

[howard38]

Great idea, count me in!

[parker1b2]

I'm in

[Wynn0013]

Wow, excellent! I would be interested.